MEX Grid Construction
Problem Overview
| Attribute | Value |
|---|---|
| Difficulty | Medium |
| Category | Construction / Math |
| Time Limit | 1 second |
| Key Technique | Constraint Satisfaction + MEX Properties |
| CSES Link | - |
Learning Goals
After solving this problem, you will be able to:
- Understand MEX (Minimum Excluded Value) and compute it efficiently
- Apply constraint satisfaction to grid construction problems
- Recognize when grid constraints are impossible to satisfy
- Construct valid grids using mathematical analysis
Problem Statement
Problem: Given an n x n grid, construct a grid filled with non-negative integers such that the MEX of each row equals a given target value m. The MEX (Minimum Excluded Value) is the smallest non-negative integer not present in a set.
Input: Two integers n and m (grid size and target MEX)
Output: Print n lines with n space-separated integers, or “IMPOSSIBLE” if no solution exists.
Constraints: 1 <= n <= 1000, 0 <= m <= n
Examples
Input: 3 2 Input: 2 3
Output: Output:
0 1 3 IMPOSSIBLE
0 1 4
0 1 5
Explanation: For n=3, m=2: each row contains {0,1} but not 2, so MEX=2. For n=2, m=3: impossible since rows need {0,1,2} but only have 2 columns.
Intuition: How to Think About This Problem
Pattern Recognition
Key Question: What must be present in a row to achieve MEX = m?
For a row to have MEX = m:
- It must contain all values from 0 to m-1 (so MEX is at least m)
- It must NOT contain the value m (so MEX is exactly m)
Key Constraint
For MEX = m in a row of length n:
- Need m required values: {0, 1, 2, ..., m-1}
- These m values must fit in n columns
- Therefore: m <= n (necessary and sufficient condition)
Analogy
Think of MEX like checking parking spots numbered 0, 1, 2, …:
- MEX is the first empty spot
- To achieve MEX = m, fill spots 0 through m-1 and leave spot m empty
Solution: Mathematical Construction
Key Insight
The Trick: If m <= n, place {0, 1, …, m-1} in each row and fill remaining cells with values > m.
Algorithm
- If m > n, return “IMPOSSIBLE”
- For each row: fill columns 0 to m-1 with values 0 to m-1
- Fill remaining columns with distinct values > m
- Output the grid
Dry Run Example
With n = 3, m = 2:
Check: m=2 <= n=3? YES
Row 0: [0, 1] + [3] = [0, 1, 3] -> MEX = 2
Row 1: [0, 1] + [4] = [0, 1, 4] -> MEX = 2
Row 2: [0, 1] + [5] = [0, 1, 5] -> MEX = 2
Visual Diagram
Target MEX = 2, Grid 3x3
Required (0 to m-1): Fill remaining (> m):
+---+---+---+ +---+---+---+
| 0 | 1 | ? | --> | 0 | 1 | 3 |
| 0 | 1 | ? | | 0 | 1 | 4 |
| 0 | 1 | ? | | 0 | 1 | 5 |
+---+---+---+ +---+---+---+
Code
Python
def mex_grid_construction(n: int, m: int) -> None:
"""
Construct n x n grid where each row has MEX = m.
Time: O(n^2), Space: O(n^2)
"""
if m > n:
print("IMPOSSIBLE")
return
filler = m + 1
for row in range(n):
current_row = list(range(m)) # Values 0 to m-1
for _ in range(m, n):
current_row.append(filler)
filler += 1
print(*current_row)
if __name__ == "__main__":
n, m = map(int, input().split())
mex_grid_construction(n, m)
Complexity
| Metric | Value | Explanation |
|---|---|---|
| Time | O(n^2) | Fill n x n grid cells |
| Space | O(1) | Output directly, no storage needed |
Common Mistakes
Mistake 1: Missing Feasibility Check
# WRONG
def wrong(n, m):
for row in range(n):
print(*list(range(m)) + [m+1]*(n-m)) # Crashes if m > n
# CORRECT
if m > n:
print("IMPOSSIBLE")
return
Mistake 2: Including m in the Row
# WRONG - gives MEX > m
row = list(range(m + 1)) # Includes m!
# CORRECT
row = list(range(m)) # Only 0 to m-1
Mistake 3: Filler Values Include m
# WRONG - filler starts at m
filler = m # MEX becomes > m!
# CORRECT - skip m
filler = m + 1
Edge Cases
| Case | Input (n, m) | Output | Reason |
|---|---|---|---|
| m = 0 | (3, 0) | Grid with no zeros | MEX = 0 means 0 absent |
| m = n | (3, 3) | 0 1 2 per row | Exactly fits |
| m > n | (2, 3) | IMPOSSIBLE | Cannot fit {0,1,2} |
| n = 1, m = 0 | (1, 0) | 1 | Single cell > 0 |
| n = 1, m = 1 | (1, 1) | 0 | Single cell = 0 |
When to Use This Pattern
Use When:
- Constructing grids with row/column MEX constraints
- Constraints involve specific values present/absent
- Each row/column can be constructed independently
Don’t Use When:
- MEX constraints on BOTH rows AND columns (more complex)
- Values must be unique across entire grid
- Problem asks for counting valid grids (use DP)
Pattern Recognition:
- MEX problem? -> Smallest missing non-negative integer
- Construction? -> Check feasibility first
- Row-only constraints? -> Rows are independent
Related Problems
Easier (Do First)
| Problem | Why It Helps |
|---|---|
| Missing Number | Finding missing values |
| Permutations | Basic construction |
Similar Difficulty
| Problem | Key Difference |
|---|---|
| Chessboard and Queens | Grid with conflict constraints |
| Grid Paths | Grid traversal |
Harder (Do After)
| Problem | New Concept |
|---|---|
| MEX Grid Construction II | Dual row/column constraints |
| Codeforces MEX Problems | Advanced MEX constructions |
Key Takeaways
- MEX Definition: Smallest non-negative integer not in a set
- Feasibility: For MEX = m with n columns, need m <= n
- Construction: Include {0..m-1}, exclude m, fill rest with values > m
- Edge Case: m = 0 means no zeros in any row
Practice Checklist
- Explain MEX and compute it for a given set
- Determine when construction is impossible
- Implement without looking at the solution
- Handle m = 0 correctly
- Solve in under 10 minutes